The force on a rocket moving with a velocity 300 m/s is 210 N .Find the rate of consumption of fuel in rocket .
Answers
Answered by
14
F = vdm/dt
dm/dt = F/v
= 210 / 300
= 0.7 kg/s
Rate of consumption of fuel is 0.7 kg/s
dm/dt = F/v
= 210 / 300
= 0.7 kg/s
Rate of consumption of fuel is 0.7 kg/s
Answered by
1
Answer:
The rate of consumption of fuel is 0.7 kg/s.
Explanation:
Given:-
Velocity of Rocket, v = 300 m/s
Force on rocket, F = 210 N
Let the rate of consumption be 'dm/dt'.
Now, we know by formula that:-
Force, F = v dm/dt
Putting the given values in the formula, we get:-
210 = 300 × dm/dt
dm/dt = 210/300
dm/dt = 0.7 kg/s
Hope it helps! ;-))
Attachments:
Similar questions