Question

the force on phonogram needle is 1.2 N. The point has a circular cross-section of radius 0.1 mm. What pressure does it exert on the record of atm​

Answer 1

Answer:

the answer is 120N.

Explanation:

                          F = 1.2

                         r =  0.1 mm = 0.1 x  10^-3m

                          p = f/a

                           = 1.2/0.1 x 10^-3            

                           = 1.2 x 10^3/0.1    

                           =  0.12 x 10^3

                           = 120N