Question

The force on the bottom of a tank is 120kg.wt .If the pressure is 12pasacals find the area

Answer 1

F= 1200 N

P = 12 Pa

P= F/A

12 = 1200/A

THEN A = 0.01 m^2

Answer 2

Given that,

Force, F = 120 kg wt = 120 × 9.8 = 1176 N

Pressure, P = 12 Pa

To find,

Area of cross section

Solution,

Pressure exerted by an object is equal to the force acting on it per unit area of cross section. It is given by :

$P=\dfrac{F}{A}$

A is area

$A=\dfrac{F}{P}\\\\A=\dfrac{1176\ N}{12\ Pa}\\\\A=98\ m^2$

So, the area of cross section of the tank is $98\ m^2$.

Learn more,

Pressure

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