Question

The forces which can push 150N body upwards along an incline of 30 with an acceleration of 5m/s2 will be

Answer 1

force required = vertical component of weight
that is acting towards the ground × acceleration
= 150 × sin30 × 5
= 150× 0.5 × 5
= 375 N

Answer 2

Given:

• Weight of mass = 150 N
• Angle of inclination = 30°
• Acceleration = 5 m/s².

To find:

• Force required ?

Calculation:

Mass of the object is :

$m = \dfrac{weight}{g} = \dfrac{150}{10} = 15 \: kg$

Now, as per the FREE-BODY DIAGRAM of mass on inclined plane, we can say:

$F - mg \sin( \theta) = ma$

$\implies F = mg \sin( \theta) + ma$

$\implies F = 150 \sin( {30}^{ \circ} ) + 15(5)$

$\implies F = 150 (0.5) + 15(5)$

$\implies F = 75 + 75$

$\implies F = 150 \: N$

So, the force required is 150 N along the inclined plane.