Question

The form of m in order that 2^m-1 may be divisible by 9and 7 both is given by

Answer 1

Step-by-step explanation:

Given The form of m in order that 2^m-1 may be divisible by 9and 7 both is given by

• Given 2^m -1 the form of m in order may be divisible by both 9 and 7 . now the LCM of 9 and 7 will be 9 x 7 = 63 . Now m should be a multiple of 6 and so 2^6 – 1 = 64 – 1 = 63.
• That is m = 6k, where k is any positive integer.