Question

The formation of of ethyl acetate from ethanol and acetic acid at 25 degree centigrade has an equilibrium constant of approximately 1.0 this implies that pen ethanol-
1. And acetic acid mix together then 50% of these would be converted to product
2. Acetic acid ethyl acetate and water are mixed together then they would be in equilibrium with one another.
3. And acetic acid are mixed together in molar mass ratio than 50% of these would be converted to product.
4. Acetic Acid Ethyl Acetate and water are mixed together in molar ratio than they would be in equilibrium with one another.​

Answer 1

Answer:

OMG....

Explanation:

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Answer 2

Formation of ethyl acetate from ethanol and acetic acid

Explanation:

Option 3. And acetic acid are mixed together in molar mass ratio than 50% of these would be converted to product

Reaction of ethyl acetate with ethanol in the presence of dilute acid is the example of esterification reaction which results in the formation of sweet smelling ester compound. Condensation of water takes place.

Esterification is an reversible reaction- depend on the concentration of reactants and products.

equilibrium constant K for the given reaction:

$C_{2}H_{5}OH + CH_{3}COOH + H^{+} --> CH_{3}COOC_{2}H_{5} + H_{2}O$

K = [ester]/[acid][alcohol]

K=1

[ethanol] [acid] = [ester]

If the concentration of reactants increase, the reaction shifts in forward direction to maintain equilibrium.

So, when ethanol and acetic acid are mixed together in molar mass ratio than 50% of these would be converted to product to maintain equilibrium.