Question

The formula h=1/2(-32)t^2+64t approximates the height, in feet, of a ball after t seconds. How high will the ball be after 1 second?​

Answer 1

Given:

The formula $h=\frac{1}{2}(-32)t^{2}+64t$ approximates the height, in feet, of a ball after $t$ seconds.

To find:

How high will the ball be after 1 second?

Step-by-step explanation:

The height formula is $h=\frac{1}{2}(-32)t^{2}+64t$

Put $t=1$ in this equation to get the required height reached by the ball after 1 second.

$\Rightarrow h=\frac{1}{2}*(-32)*1^{2}+64*1$

$\Rightarrow h=\frac{1}{2}*(-32)+64$

$\Rightarrow h=-16+64$

$\Rightarrow h=48$

Answer:

Therefore the required height is 48 feet.