Question

The formula mass of Ca3(PO4)2 is. ( Atomic mass of Ca = 40 , P= 31, O =16) *



a)103 g

b)301 g

c)310 g

d)113 g




​

Answer 1

Answer:

Explanation:

here is your answer

a} 103 g

Answer 2

Option(B)

$Ca_{3}(PO_{4})_{2}$

Molecular mass of compound;

$Ca_{3}(PO_{4})_{2}$

$=3×40+2(31+(16×4))$

$=120+2(31+64)$

$=120+2(95)$

$=120+180$

$\color{orange}\therefore atomic\:mass=300g$

(301 is the actual ans but we got 300 because of taking approximate values of atomic masses of elements)

HOPE THAT HELPS!!