The formula of a chloride of a metal M is MCL 2 write the formula of its sulphate zincate hydroxide
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Answer:
Hcl + zn(oh)2= zncl2 + h2o
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The answers with respect to metal M is given below-
The compound given in question is MCl2. Here, two ions of chlorine are present.
Since chlorine has valency of -1 thus total charge will be -2 on chlorine molecules in given compound. To make net charge zero, M must have +2 charge and hence it's valency.
Now, sulphate has -2 charge. So formula of metal sulphate will be - MSO4.
Zincate is represented as Zn(OH)4(2-) also referred to as tetrahydroxozincate ion. The charge is -2 on this ion. So again, compound formed will be-
MZn(OH)4.
To form metal hydroxide, one ion of metal will react with two molecules of hydroxyl ions containing charge of -2. M(OH)2 will be the formula.
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