Question

the formula of metal oxide is z203 if 6mg of hydrogen is required to complete the reduction of 0.1596 g of metal oxide .then atomic weight of an atom is.......​

Answer 1

Answer:

The atomic weight of metal in metal oxide is 55.8 gm

Explanation:

From the given question, we get the chemical equation as :

We are also given that 6 mg of reduces 0.1596 gm of

Or

reduces 0.1596 gm of

So, 1 gm of will reduce of  = 26.6 gm of

Equivalent weight of  = 26.6

Equivalent weight of M + Equivalent weight of O = 26.6

We know that equivalent weight of O = 8

So, Equivalent Weight of M + 8 = 26.6

Equivalent weight of M = 26.6 - 8 = 18.6

Valency of the metal in  is 3. This is because it forms an oxide of the form  and belongs to Group III in the periodic table. Group III elements have 13 electrons and 3 electrons in their valence shell making their valency as 3.

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