The formula of oxide of metal whose successive ionization enthalpies are
10,20,50,2000kjmol respectively
1.m2o
2.m2o3
3.mo
4.mo2
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Option is 2)M2O3 bcoz 10 20 50 are nearer to one other but 2000 there is a sudden jump in value and we know that oxygen valence 2 and now M value 3 by crisscrossing we get M2O3
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