Question

The formula of the compound is A2B5. The number of electrons in the outermost orbits of A and B respectively
are
(2) 5 and 6
(4) 2 and 3
А A
(1) 6 and 3
(3) 5 and 2​

Answer 1

AA

2 and 3

5 and 2

5 and 6

6 and 3