Question

The formula of the compound is A2B5. The number of electrons in the outermost orbits of A and B respectively
(1)6 and 3
(2) 5 and 6
(4) 2 and 3
(3)5 and 2


please send me the explanation...
​

Answer 1

For the formula of the compound A2B5

Also can be written as A5+B2−

Therefore, A has 5 electrons in its outermost shell.

oxidation state +5. and B shows oxidation state −2, therefore, it is deficient of 2 electrons.

Hence its outermost shell has 8−2=6 electrons

Answer 2

Answer:

For the formula of the compound A2B5

Also can be written as A

5+ B2−

Therefore, A has 5 electrons in its outermost shell.

oxidation state +5. and B shows oxidation state −2, therefore, it is deficient of 2 electrons.

Hence its outermost shell has 8−2=6 electrons

So, the correct option is B.

Hope this is helpful for you.