The formula of the compound is a2b5 the number of electrons on the outermost orbitals of a and b respectively are
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The formula of the compound is A2B5
A^5.B^2 compound
So, A has 5 electrons in its outermost shell.
(i.e) Why it can shown oxidation state of +5.
and B shows oxidation state of -2 i.e it is deficient of 2 electrons .
So its outer most shell has 8-2 i.e 6 electrons
A^5.B^2 compound
So, A has 5 electrons in its outermost shell.
(i.e) Why it can shown oxidation state of +5.
and B shows oxidation state of -2 i.e it is deficient of 2 electrons .
So its outer most shell has 8-2 i.e 6 electrons
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