Math, asked by pranali3183, 2 months ago

The four angles of a parallelogram ABCD are in the ratio of 1:4:1:4. Find all the four angles.

Answers

Answered by MoodyCloud
27

Answer:

  • All four angles of parallelogram are 36°, 144°, 36° and 144°.

Step-by-step explanation:

Given :-

  • Ratio of four angles of parallelogram is 1:4:1:4.

To find :-

  • Four angles of parallelogram.

Solution :-

Let, All angles of parallelogram be 1x or x, 4x , x and 4x.

We know,

Sum of all four angles of parallelogram is 360°.

So,

 \rightarrow x + 4x + x + 4x = 360°

 \rightarrow 10x = 360°

 \rightarrow x = 360°/10

 \rightarrow x = 36°

Verification :-

 \rightarrow x + 4x + x + 4x = 360°

  • Put x = 36°

 \rightarrow 36° + 4×36° + 36° + 4×36° = 360°

 \rightarrow 36° + 144° + 36° + 144° = 360°

 \rightarrow 360° = 360°

 \boxed{\sf Hence\: Verified.}

Angles :

x = 36°

4x = 144°

x = 36°

4x = 144°

Therefore,

All four angles of parallelogram are 36°, 144°, 36° and 144°.

Answered by Anonymous
9

Correct Question-:

The four angles of a parallelogram ABCD are in the ratio of 1:4:1:4. Find all the four angles.

AnswEr -:

  • \boxed{\blue{\sf{\star{\:\:All\:four\:angles\:of\:Parallelogram \:is\:36⁰,144⁰,36⁰\:and\:144⁰}}}}

Explanation-:

Given ,

  • The four angles of a parallelogram ABCD are in the ratio of 1:4:1:4.

To Find ,

  • The all four angles of parallelogram.

Figure related to the question-:

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,1)(1,1)(6,1)\put(0.4,0.5){\bf D}\qbezier(1,1)(1,1)(1.6,4)\put(6.2,0.5){\bf C}\qbezier(1.6,4)(1.6,4)(6.6,4)\put(1,4){\bf A}\qbezier(6,1)(6,1)(6.6,4)\put(6.9,3.8){\bf B}\end{picture}

Solution -:

☆ Let the four angles of parallelogram be -:

  • 1st angle -: ( Angle )¹ = 1 x ⁰
  • 2nd angle -: ( Angle )² = 4 x ⁰
  • 3rd angle-: ( Angle)³ = 1 x ⁰
  • 4th angle -; ( Angle )⁴ = 4 x ⁰ .................[1]

As we know that ,

\boxed{\blue{\sf{\star{\:Sum \:of\:all\:four\:angles\:of\:Parallelogram \:is\:360⁰}}}}

or ,

\boxed{\blue{\sf{\star{\:(Angle)_{1} +( Angle)_{2}+ (Angle )_{3}+ (Angle)_{4} =\:360⁰}}}}

Here ,

  • 1st angle -: ( Angle )¹ = 1 x ⁰
  • 2nd angle -: ( Angle )² = 4 x ⁰
  • 3rd angle-: ( Angle)³ = 1 x ⁰
  • 4th angle -; ( Angle )⁴ = 4 x ⁰ .................[From 1]

Now ,

  • \pink{\sf{\rightarrow {1x + 4x + 1x + 4x = 360⁰ }}}
  • \pink{\sf{\rightarrow { 2x + 8x = 360⁰ }}}
  • \pink{\sf{\rightarrow {10x = 360⁰ }}}
  • \pink{\sf{\rightarrow {x =\frac { 360}{10} }}}
  • \pink{\sf{\rightarrow {x = 36⁰ }}}

Therefore,

  • \boxed{\blue{\sf{\star{\:x = 36⁰}}}}

Now ,

☆ Four Angles of parallelogram are -:

  • 1st angle -: ( Angle )¹ = 1 x = 1 × 36 = 36
  • 2nd angle -: ( Angle )² = 4 x = 4 × 36 = 144
  • 3rd angle-: ( Angle)³ = 1 x = 1 × 36 = 36
  • 4th angle -; ( Angle )⁴ = 4 x = 4 × 36

Hence ,

  • \boxed{\blue{\sf{\star{\:\:All\:four\:angles\:of\:Parallelogram \:is\:36⁰,144⁰,36⁰\:and\:144⁰}}}}

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