Question

the four angles of a quadrilateral are2(x-10)°,(x+30)°,(x+50)° and 2x°. find all the four angles.​

Answer 1

Answer: 50 Degrees is value of x so angles are 80;80;100;100

Step-by-step explanation:

We know that sum of all angles in a quadrilateral is 360 degrees

2X-20+X+30+X+50+2X= 360

6X+60= 360

6X= 300

X= 300/6

X= 50 degrees.

So angles are 80;80;100;100

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Answer 2

Given,

Four angles of a quadrilateral are 2(x-10)°, (x+30)°, (x+50)° and 2x°

Sum of all angles in a quadrilateral = 360°

According to the problem,

2(x-10)°+ (x+30)°+ (x+50)° +2x° = 360

2x - 20 + 4x°+ 80° = 360

6x + 60 = 360

6x = 360 - 60

6x = 300

x = 300/6

x = 50

Then the angles are :

2x = 2(50) = 100°

2(x - 10)° = 2(50 - 10) = 2(40) = 80°

(x + 50)° = 50 + 50 = 100°

(x + 30)° = 50 + 30 = 80°