the four angles of a quadrilateral form an AP .IF the sum of first three angle s is twice the fourth angle , then find all the angles
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a+b+c+d=360 sum of angles of a quadrilateral
a+b+c=2d given
2d+d=360
3d=360
d=120
using ap
sum=n/2 (a+l)
360=4/2 (a+120)
resolving above equation
a=60
hence b=80
c=100
and d=120
a+b+c=2d given
2d+d=360
3d=360
d=120
using ap
sum=n/2 (a+l)
360=4/2 (a+120)
resolving above equation
a=60
hence b=80
c=100
and d=120
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