Math, asked by pragnasr988, 7 months ago

The four angles of all quadrilateral are in the ratio 1:2:3:4. Find the measure of each angle

Answers

Answered by handsomeram16645
6

solution

solutionLet the angles of quadrilateral be

solutionLet the angles of quadrilateral bex, 2x, 3x , 4x

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°10x = 360°

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°10x = 360°x = 360/10 = 36°

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°10x = 360°x = 360/10 = 36°Ans. the four angles are :-

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°10x = 360°x = 360/10 = 36°Ans. the four angles are :-x = 36°

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°10x = 360°x = 360/10 = 36°Ans. the four angles are :-x = 36°2x = 2 × 36 = 72°

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°10x = 360°x = 360/10 = 36°Ans. the four angles are :-x = 36°2x = 2 × 36 = 72°3x = 3 × 36 = 108°

solutionLet the angles of quadrilateral bex, 2x, 3x , 4xsum of all angles of quadrilateral = 360°x + 2x + 3x + 4x = 360°10x = 360°x = 360/10 = 36°Ans. the four angles are :-x = 36°2x = 2 × 36 = 72°3x = 3 × 36 = 108°4x = 4 × 36 = 144°

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Answered by karthikvijai05
3

Answer:

let the angles be y

Step-by-step explanation:

Then

1y +2y+3y+4y=360

10y=360

y=36

first angle =1*36=36

second angle=2*36=72

third angle=3*36=108

fourth angle=4*36=144

144+108+72+36=360

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