Question

The four angles of quadrilateral form an A.P. if the sum of the first three angles is twice the fourth angle, then find all the angles.

Answer 1

$x - 3y + x - y + x + y + x + 3y = 360 \\ 4x = 360 \\ x = 90 \\ x - 3y + x - y + x + y = 2(x + 3y) \\ 3x - 3y = 2x + 6y \\ 9y = x \\ 9y = 90 \\ y = 10 \\ so \: angles \: are \: 60.80.100.120$

Answer 2

Answer:

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