the four sides of quadrilateral ABCD are tangential to a circle if BD is 7.2,DA is 6.9,BC is 8.5,then find CD
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Let ABCD be the points where the circle touches the quadrilateral
From a point out side of the circle the two tangents to the circle are equal.
AP = AS, BP = BQ , CR = CQ , and DR = DS
Adding AP + BP + CR + DR = AS + BQ + CQ + DS
AB + CD = AD + BC
So, option B is the answer.
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