The four small spheres shown in figures carry charges q1 = 4nc - 7.8nC,q3=2.4nC andq4= 1 6nC Calculate thefluxpassingthrough each of the threeclosed surfaces S1, S2, and S3 in figures.
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Explanation:
Given The four small spheres shown in figures carry charges q1 = 4 nc - 7.8 nC, q3 = 2.4 nC and q4= 1 6 nC Calculate the flux passing through each of the three closed surfaces S1, S2, and S3 in figures.
- First we need to find flux.
- So flux φ =closed ∫E.ds
- = q enclosed / εo
- So flux of s1 will be
- So φ (s1) = q1 / εo (1/4πεo = 9 x 10^9
- Or 1 / εo = 9 x 4π x 10^9 )
- = 4 x 10^-9 x 9 x 4π x 10^9
- = 16 π x 9
- = 452.16 Nm^2 / C
- Similarly for flux of s2 will be
- So φ(S2) = q2 / εo
- = - 7.8 x 10^-9 x 9 x 4π x 10^9
- = - 7.8 x 9 x 4π
- = 881.71 Nm^2 / C
- Similarly for flux of s3 will be
- So φ(s3) = q1 + q2 / εo
- = (4 – 7.8 ) 10^-9 x 9 x 4π x 10^9
- = - 3.8 x 9 x 4π
- = - 429.55 Nm^2 / C
Therefore flux passing through three closed surfaces will be 452.16 Nm^2/C, 881.71 Nm^2/ C, 429.55 Nm^2 / C
Reference link will be
https://brainly.in/question/19461169
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