Question

The four walls and ceiling of a room are to be repaired. The length and breadth of the room are 8 m and 4 m and its height 3 m. Find the cost of repair at rupees 30 per m² ​

Answer 1

Answer:

Total surface area of the cubiodal room=2[(8×4)+(8×3)+(4×3)]=2[32+24+12]=136

Area of the of rectangular floor(to be excluded)=8×4=32m²

Area of 4 walls and the ceiling, =136−32=104m²

Cost of repair Rs.30 per m²

,=Rs.3120