Question

The four walls and the ceiling of a cuboidal room need to be plastered. If the length, width and height of the room are 6 m,8 m and 10 m respectively, find the area to be plastered.

Answer 1

Answer:

6*8*10 = area

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Area of four walls = 2 ( lb + bh) + Ceiling that is lb

= 2 ( 6×8 + 8×10 ) + 6 ×8

= 2 ( 48 + 80 ) + 48

= 2 × 128 + 48

= 256 + 48

= 304 m^2

Thus area to be plastered is 304 m^2