Question

the four walls and the ceiling of a room are to be repaired the length and breadth of room are 8m and 4m and it's height is 3m find the cost of repair at rupees 50 per m2

Answer 1

Answer:

Total surface area of the cubiodal room=2[(8×4)+(8×3)+(4×3)]=2[32+24+12]=136

Area of the of rectangular floor(to be excluded)=8×4=32m

2

Area of 4 walls and the ceiling, =136−32=104m

2

Cost of repair Rs.30 per m

2

,=Rs.3120