The Fourier cosine transfor
of f(x) = 2e-5x + 5e-2x
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Answer:
Find the four sine transform 5e−2x+2e−5x
A) 2π−−√[1s2+4+1s2+25]
B) 2π−−√[2s2+4+5s2+25]
C) 102π−−√[1s2+4+1s2+25]
D) 2π−−√[2s2−4+5s2−25]
Correct Answer:
C) 102π−−√[1s2+4+1s2+25]
Description for Correct answer:
Formula :
Fs(e−ax)=2π−−√(as2+a2)
Fs[5e−2x+2e−5x]
=5Fs(e−2x)+2Fs(e−5x)
=525−−√(2s2+4)+22π−−√(5s2+25)
=102π−−√(1s24+1s2+25]
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