Math, asked by chhayatikhe29, 3 months ago

the fourier cosine transform of f(x) = 2e^-5x+5e^-2x

Answers

Answered by digvijay151274

0

Answer:

Description for Correct answer:

Formula :

Fs(e−ax)=2π−−√(as2+a2)

Fs[5e−2x+2e−5x]

=5Fs(e−2x)+2Fs(e−5x)

=525−−√(2s2+4)+22π−−√(5s2+25)

=102π−−√(1s24+1s2+25]

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