Math, asked by kawalb77001, 4 months ago

The Fourier series of odd function in the interval ( C C + 2π) has only
– term

Answers

Answered by IshuSamu
0

Step-by-step explanation:

Baron Jean Baptiste Joseph Fourier

(

1768

1830

)

introduced the idea that any periodic function can be represented by a series of sines and cosines which are harmonically related.

Baron Jean Baptiste Joseph Fourier (1768−1830)

Fig.1 Baron Jean Baptiste Joseph Fourier (1768−1830)

To consider this idea in more detail, we need to introduce some definitions and common terms.

Basic Definitions

A function

f

(

x

)

is said to have period

P

if

f

(

x

+

P

)

=

f

(

x

)

for all

x

.

Let the function

f

(

x

)

has period

2

π

.

In this case, it is enough to consider behavior of the function on the interval

[

π

,

π

]

.

Suppose that the function

f

(

x

)

with period

2

π

is absolutely integrable on

[

π

,

π

]

so that the following so-called Dirichlet integral is finite:

π

π

|

f

(

x

)

|

d

x

<

;

Suppose also that the function

f

(

x

)

is a single valued, piecewise continuous (must have a finite number of jump discontinuities), and piecewise monotonic (must have a finite number of maxima and minima).

If the conditions

1

and

2

are satisfied, the Fourier series for the function

f

(

x

)

exists and converges to the given function (see also the Convergence of Fourier Series page about convergence conditions.)

At a discontinuity

x

0

, the Fourier Series converges to

lim

ε

0

1

2

[

f

(

x

0

ε

)

f

(

x

0

+

ε

)

]

.

The Fourier series of the function

f

(

x

)

is given by

f

(

x

)

=

a

0

2

+

n

=

1

{

a

n

cos

n

x

+

b

n

sin

n

x

}

,

where the Fourier coefficients

a

0

,

a

n

,

and

b

n

are defined by the integrals

a

0

=

1

π

π

π

f

(

x

)

d

x

,

a

n

=

1

π

π

π

f

(

x

)

cos

n

x

d

x

,

b

n

=

1

π

π

π

f

(

x

)

sin

n

x

d

x

.

Sometimes alternative forms of the Fourier series are used. Replacing

a

n

and

b

n

by the new variables

d

n

and

φ

n

or

d

n

and

θ

n

,

where

d

n

=

a

2

n

+

b

2

n

,

tan

φ

n

=

a

n

b

n

,

tan

θ

n

=

b

n

a

n

,

we can write:

f

(

x

)

=

a

0

2

+

n

=

1

d

n

sin

(

n

x

+

φ

n

)

or

f

(

x

)

=

a

0

2

+

n

=

1

d

n

cos

(

n

x

+

θ

n

)

.

Fourier Series of Even and Odd Functions

The Fourier series expansion of an even function

f

(

x

)

with the period of

2

π

does not involve the terms with sines and has the form:

f

(

x

)

=

a

0

2

+

n

=

1

a

n

cos

n

x

,

where the Fourier coefficients are given by the formulas

a

0

=

2

π

π

0

f

(

x

)

d

x

,

a

n

=

2

π

π

0

f

(

x

)

cos

n

x

d

x

.

Accordingly, the Fourier series expansion of an odd

2

π

-periodic function

f

(

x

)

consists of sine terms only and has the form:

f

(

x

)

=

n

=

1

b

n

sin

n

x

,

where the coefficients

b

n

are

b

n

=

2

π

π

0

f

(

x

)

sin

n

x

d

x

.

Below we consider expansions of

2

π

-periodic functions into their Fourier series, assuming that these expansions exist and are convergent.

Similar questions
Science, 10 months ago