Math, asked by archanagautam3817, 2 months ago

the fourier sine ran form of
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Answers

Answered by nd776201gimalcom
7

Answer:

Summarizing all this work up the Fourier sine series of an odd function f(x) on −L≤x≤L − L ≤ x ≤ L is given by, f(x)=∞∑n=1Bnsin(nπxL)Bn=1L∫L−Lf(x)sin(nπxL)

Answered by preethipreet0987
0

Answer:

i don't understand your question

Step-by-step explanation:

sorry

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