The fourth proportional to (a^2 - ab +b^2), (a^3 + b^3) and (a - b) is equal to
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Answer:
The fourth proportional = a² -b²
Step-by-step explanation:
To find,
The fourth proportional to (a² - ab +b²), (a³ + b³) and (a - b)
Recall the concepts
- If four number a,b,c,d are in proportion, then we have a×d = b×c
here a, b,c,d are called the first , second, third and fourth proportional
- (a³ + b³) = (a+b)(a² - ab +b²)
Solution:
Let the fourth proportional be 'x' then we have,
(a² - ab +b²), (a³ + b³) ,(a - b), x are in proportion
Then (a² - ab +b²)x = (a³ + b³) ×(a - b)
Substituting the identity (a³ + b³) = (a+b)(a² - ab +b²)
(a² - ab +b²)x =(a+b)(a² - ab +b²)×(a - b)
Cancelling (a² - ab +b²), on both sides we get
x = (a+b)(a-b)
x= a² -b²
The fourth proportional = a² -b²
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