Math, asked by chakrawartienoch, 9 months ago

The fourth proportional to (a^2 - ab +b^2), (a^3 + b^3) and (a - b) is equal to​

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Answered by preeth3
18
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Solution
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Answered by smithasijotsl
1

Answer:

The fourth proportional = a² -b²

Step-by-step explanation:

To find,

The fourth proportional to (a² - ab +b²), (a³ + b³) and (a - b)

Recall the concepts

  • If four number a,b,c,d are in proportion, then we have a×d = b×c

here a, b,c,d are called the first , second, third and fourth proportional

  • (a³ + b³) = (a+b)(a² - ab +b²)

Solution:

Let the fourth proportional be 'x' then we have,

(a² - ab +b²), (a³ + b³) ,(a - b), x are in proportion

Then (a² - ab +b²)x = (a³ + b³) ×(a - b)

Substituting the identity  (a³ + b³) = (a+b)(a² - ab +b²)

(a² - ab +b²)x =(a+b)(a² - ab +b²)×(a - b)

Cancelling (a² - ab +b²), on both sides we get

x = (a+b)(a-b)

x=  a² -b²

The fourth proportional = a² -b²

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