The fourth term of a geometric progression is 2 by 3 and 7th term is 16 by 81 find the geometrical series
Answers
Answered by
1
Answer:
9/4 , 3/2 , 1 .......
Step-by-step explanation:
4th term =2/3 7th term = 16/81
ar³ = 2/3 equ (1) ar power6 = 16/81 equ (2)
(2)÷ (1) ⇒ r³ = 8 / 27
∴ r = 2/3
subtitute r = 2/3 in equ (1)
a r³ = 2/3
a x 8/27 = 2/3
a = 9/4
geometrical series a, ar , ar².........
9/4 ,3/2 , 1 . . . .
Similar questions