the fourth term of an ap is 11 the sum of 5th and 7th term of the ap is 24 find the common difference
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t4 = 11 = a+3d ......................... 1
t5 + t7 = 24
a + 4d + a + 6d = 24
2a + 10d = 24
a + 5d = 12 ..............................2
Equating eq 1 and 2
a + 5d = 12
a + 3d = 11
________
2d = 1
d = 1/2
________
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common difference of is equal to 1/7
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