The fourth term of an AP is 11.the sum of the fifth and seventh term of anAP is 24.find common differences
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Answer: d=0.5
Step-by-step explanation: fourth term = 11
a+3d=11 since tn= a+(n-1)d;
now 5 th term + 7 th term = 24
a+4d+a+6d=24; 2a+10d=24; a+5d=12;
solve a+3d=11 and a+5d=12;
we get subtract 2nd equation from 1st equation then we get
2d=1; d=0.5
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