the fourth term of an AP is equal to 3 times the first term and the seventh term exceed twice the third term find first tern and 29th term?
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let first term of AP is a and d is the common difference .
now
according to question
4th term =3 (1st term)
a+3d=3a
3d=2a -------(1)
again question ask
7th term - (3rd term )=2
a+6d-a-2d=2
4d=2
d=1/2
so, a=3/2 x 1/2=3/4 {from equation (1)
so, first term =3/4
and
29th term=a+28d=3/4+28 x 1/2=3/4+14
=57/4
now
according to question
4th term =3 (1st term)
a+3d=3a
3d=2a -------(1)
again question ask
7th term - (3rd term )=2
a+6d-a-2d=2
4d=2
d=1/2
so, a=3/2 x 1/2=3/4 {from equation (1)
so, first term =3/4
and
29th term=a+28d=3/4+28 x 1/2=3/4+14
=57/4
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