Question

The fourth term of an ap is equal to three times tge first and sventh term exceeds

Answer 1

Answer:

Step-by-step explanation:

Let a be the first term and d be the common difference of the A.P

From given conditions:

T4 = 3T1 a + 3d = 3a 2a = 3d   ... (i)

and T7 = 2T3 + 1 a + 6d = 2 (a + 2d) + 1

a + 6d = 2a + 4d + 1 2d = a + 1 ...(ii)

Substituting the value of a from (i) in (ii), we get

d=2

Substituting this value of d in (i), we get

2a = 6

=> a = 3

Hence, the first term = 3 and the common difference = 2.

Hope this helps! :)