The fourth term of an ap is zero prove that the 25th term of an ap is 3 times its 11th term
Answers
Answered by
10
Answer:
a+3d=0
a= -3d
25th term = a+24d = -3d+24d=21d
11 th term = a+10d = -3d+10d= 7d
21d= 3* 7d
Hence 25th term is three time the 11th term
Hope its help you ❤
Answered by
15
☆Given
t4=0
To prove:-
T25= 3×t11
Proof
t4=a+(n-1)d
0 =a+3d
a=-3d
Now,25 th term
25=a+(n-1)d
=>-3d+(25-1)d
21d
Now 11th term
t11=a+(n-1)d
=>-3d+10d
7d
ATQ
multiply by 3
=7d×3
=21
Here if we multiply the 11th term by 3 it equals to the 25th term
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