Math, asked by Anonymous, 11 months ago

The fourth term of an ap is zero prove that the 25th term of an ap is 3 times its 11th term​

Answers

Answered by Anonymous
10

Answer:

a+3d=0

a= -3d

25th term = a+24d = -3d+24d=21d

11 th term = a+10d = -3d+10d= 7d

21d= 3* 7d

Hence 25th term is three time the 11th term

Hope its help you ❤

Answered by Abhishek474241
15

Given

t4=0

To prove:-

T25= 3×t11

Proof

t4=a+(n-1)d

0 =a+3d

a=-3d

Now,25 th term

25=a+(n-1)d

=>-3d+(25-1)d

21d

Now 11th term

t11=a+(n-1)d

=>-3d+10d

7d

ATQ

multiply by 3

=7d×3

=21

Here if we multiply the 11th term by 3 it equals to the 25th term

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