Question

The fourth term of an arithmethic sequence is 23 and the eleventh term is 65 . Find the 100th term

Answer 1

Answer:

a+3d=23 (1) eq'n

a+10d=65 (2)eq'n

Step-by-step explanation:

applying elimination method

a+3d=23

a+10d=65

- - -

-7d=-42

d=6

put in (1)

a+3×6=23

a=23-18

a=5

100term=a+99d

5+99×6

5+ 594

599