The fourth term of AP is 24 and 44th term is 124. find t24
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t4=24
t44=124
t24=?
t4=t+3d=24----(1)
t44=t+43d=124----(2)
solving both the equations-
t+43d-(t+3d) =124-24
t+43d-t-3d=100
40d=100
d=5/2
substitute the value of d in eq(1)
t+3*5/2=24
t+15/2=24
t=24-15/2
t=48/2-15/2
t=33/2
now finding the 24th term
t24=t+23d
=33/2+23*5/2
=33/2+115/2
=148/2
=74
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