the fourth term of AP is zero prove that its 25th term is triple its 11th term
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4th term= a+3d=0
a=-3d
now
11th term= a+10d
=-3d+10d
=7d.........(i)
25th term
a+24d
=-3d+24d
=21d
= 3(7d)
=3×11th term (from eqn (i) )
therefore its prove
a=-3d
now
11th term= a+10d
=-3d+10d
=7d.........(i)
25th term
a+24d
=-3d+24d
=21d
= 3(7d)
=3×11th term (from eqn (i) )
therefore its prove
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