Question

The fourth term of gp is 2/3 and seventh term is 16/81 find the geomentric series

Answer 1

Answer:

(2/3)^-2,(2/3)^-1,(2/3),(2/3)^2.........................

Step-by-step explanation:

Let a is first term and r is ratio

then T4=ar^3=2/3-------------!)1

T7=ar^16=16/81

T7/T4=ar^6/ar^3=16/81*3/2=16*3/81*2

r^3=8/27

r^3=(2/3)^3

r=2/3

a(2/3)^3=2/3

a=(2/3)^(1-3)=(2/3)^-2

hence GP is

(2/3)^-2,(2/3)^-1,(2/3),(2/3)^2.........................