The fourth term of the sequence, whose sum of n terms is given by (-1)-1 n(n-1) is
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Given:
The sum of n terms is given by (-1)-1 n(n-1) is
To find:
The fourth term of the sequence is?
Solution:
From given, we have,
The sum of n terms is given by (-1)-1 n(n-1) is
Sn = (-1) -1 × n(n - 1) = 1 × n(n - 1) = n(n - 1)
S1 = (-1) -1 × 1(1 - 1) = 0
t1 = 0
S2 = (-1) -1 × 2(2 - 1) = 1 × 2
t2 = 2 - 0 = 2
S3 = (-1) -1 × 3(3 - 1) = 1 × 6 = 6
t3 = 6 - 2 = 4
S4 = (-1) -1 × 4(4 - 1) = 1 × 12 = 12
t4 = 12 - 6 = 6
Therefore, the fourth term of the sequence is 6
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