The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,3), B(6,7) C(10,3) will be
(2,-1)
(3,2)
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Answered by
2
Answer:
D (2, - 1)
Step-by-step explanation:
The diagonals of a parallelogram bisect each other, then let's use middle point of diagonals:
Coordinates of midpoint of AC [(- 2 + 10) / 2, (3 + 3) / 2] = (4, 3) ,
(4, 3) is coordinate of midpoint of BD.
B(6, 7) and D(x, y)
(6 + x) / 2 = 4 ==> x = 2 ,
(7 + y ) / 2 = 3 ==> y = - 1
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Answered by
1
Answer:
heloo!
here is ur answer!
let the fourth corner is (x,y)
in a parallelogram diagnols intersect each other
x+6/2=10-2/2
X =2
y+7/2=3+3/2
y=-1
so D =(2,-1)
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