Math, asked by Anonymous, 10 months ago

The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,3), B(6,7) C(10,3) will be

(2,-1)

(3,2)​

Answers

Answered by Anonymous
2

Answer:

D (2, - 1)

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, then let's use middle point of diagonals:

Coordinates of midpoint of AC [(- 2 + 10) / 2, (3 + 3) / 2] = (4, 3) ,

(4, 3) is coordinate of midpoint of BD.

B(6, 7) and D(x, y)

(6 + x) / 2 = 4 ==> x = 2 ,

(7 + y ) / 2 = 3 ==> y = - 1

Attachments:
Answered by Aristotle3081
1

Answer:

heloo!

here is ur answer!

let the fourth corner is (x,y)

in a parallelogram diagnols intersect each other

x+6/2=10-2/2

X =2

y+7/2=3+3/2

y=-1

so D =(2,-1)

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