The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,3) , B(6,7) , C(10,3) is __________.
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Let the fourth vertex D =(x,y)
We know that the diagonals of a parallelogram bisect each other. So,the midpoint of AC is same as the mid point of BD.
Mid point of two points (x1,y1 ) and (x2 ,y2 ) is calculated by the formula ( x1+x2/2) , (y1+y2)
So, midpoint of AC= Mid point of BD
=>( −2+10/2 , 3+3/2 ) = ( 6+x/2 , 7+y/2 )
=>( 4/2 ,6/2) = ( 6+x/2 , 7+y/2 )
=> 6+x = 4 , 7+y = 6
=> x = -2 , y = -1
=>x= -2 ; y = -1
Hence, D=(-2,−1)
hope it helps you
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