Question

The fourth vertex of a parallelogram ABCD whose
three vertices are A(1, 1), B(6, 1) and C(8 5) is​

Answer 1

Step-by-step explanation:

Since, ABCD is a parallelogram, therefore diagonals AC and BD will bisect each other. Hence, L and M are the same points. Hence, the fourth vertex of parallelogram is D s (x , y ) s (0,-1).

Answer 2

Answer:

D(3,5)

Step-by-step explanation:

Given the three vertices are

A(1,1) , B(6,1) ,C(8,5)

Let the forth vertex be D(x,y)

Now. in a parallelogram diagonals bisect each other

Hence, Mid point of AC = Mid point of BD

Mid point of the line segment joining the points (x1,y1) and (x2,y2) =( x1+x2 , y1+y2)

2 2

So,

(6+x , 1+y) = (1+8 , 1+5)

2 2 2 2

Hence , 6+x = 9 and 1+y = 6

2 2 2 2

6+x= 9 and 1+y =6

x= 3 and y= 5

So point D(x,y) means D(3,5)