Question

The fraction B/3x-1 is subtracted from the fraction A/2x+3. The resulting fraction is-11/(2x+3)(3x-1). Then find A + B.​

Answer 1

Answer:

always .................

Answer 2

Given:

The fraction $\frac{B}{3x-1}$ is subtracted from the fraction $\frac{A}{2x+3}$ and the resulting fraction is $\frac{-11}{(2x+3)(3x-1)}$.

To find:

The value of $A+B$.

Step-by-step explanation:

Now, $\frac{-11}{(2x+3)(3x-1)}$

$=\frac{-2-9}{(2x+3)(3x-1)}$

$=\frac{2(3x-1)-3(2x+3)}{(2x+3)(3x-1)}$

$=\frac{2}{2x+3}-\frac{3}{3x-1}$

This can be equated with

$\quad \frac{A}{2x+3}-\frac{B}{3x-1}$.

Thus $A=2,\:B=3$.

Now, $A+B=2+3=5$

Answer:

The value of $A+B$ is 5.