The fraction obtained by dividing a two digit number by the number obtained by reversing the digits is 8/3. The sum of the number is 9. Find the original number.
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HERE'S YOUR ANSWER....✌️✌️
HERE'S YOUR ANSWER....✌️✌️The equation is ,
HERE'S YOUR ANSWER....✌️✌️The equation is ,x+y =9........(i)
HERE'S YOUR ANSWER....✌️✌️The equation is ,x+y =9........(i)10x + y = (10y + x)-9 ........(ii)
HERE'S YOUR ANSWER....✌️✌️The equation is ,x+y =9........(i)10x + y = (10y + x)-9 ........(ii)the original number is 10x + y
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Given:
- We have been given a number which when divided by the number obtained by reversing its digit gives a fraction 8/3
- Sum of digits of number is 9
To Find:
- We have to find the original number
Solution:
Let Tens digit of number = x
Unit digit of number = y
Given that sum of digit is 9
---------- 1
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The fraction obtained by dividing a two digit number by the number obtained by reversing the digits is 8/3
Cross Multiplying the Terms
Substituting the values of y from Equation 1
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Putting x = 7 in Equation 1 , we get
Original number is as follows :
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☞ The fraction obtained by dividing a two digit number by the number obtained by reversing the digits is 8/3
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