Question

The fraction of a floating object of volume V₀ and density
d₀ above the surface of liquid of density d will be
(a)d₀/d - d₀
(b)d - d₀/d
(c)d₀/d
(d)d₀d/d + d₀​

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Answer 1

Answer:

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Explanation:

Correct option is

B

dd−d0

Let x be the fraction of volume of object floating above the surface of the liquid.

As weight of liquid displaced = weight of object

∴(V0−xV0)dg=V0d0g

(1−x)d=d0 or x=1−dd0=dd−d0

Answer 2

Answer:

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Explanation: