Question

The fraction of ice that melts by mixing equal masses of ice at 10°C and
water at 60°C is​

Answer 1

Answer:

11/16

Explanation:

ice=10and water=60

m. m

60m=10×0.5=5m

55m

55m/80m=11/16

Answer 2

Answer

The fraction of ice that melts by mixing equal masses of ice $\frac{5}{16}$

Explanation

Let in be initial masses and water and ice and $x$ be the mass of ice melting . So, Heat absorbed $= m s\left|\Delta T_{\text {ice }}\right|+x L_{f}$

$\Delta \theta absorbed =m(1)(10)+x(80)$

Heat released $=m s \Delta T$ water

$\Delta H released =m(1)(60) \\ \Delta H released =60 \mathrm{~m}$

As $\Delta \theta observed =\Delta H$ released

$\Rightarrow 10 m+80 x=60 m \\ \Rightarrow 80 x=50 m \Rightarrow x=\frac{5}{8} m$

Fraction of ice melted $=\frac{x}{2 m}\\=\frac{5}{8} m\\=\frac{5}{16}$