the fraction (X + 3 ) / ( X + 2 ) are the form of
Answers
Answered by
0
Answer:
y=
x
3
+1
x
2
+1
=
(x+1)(x
2
−x+1)
x
2
+1
∴y=
x+1
A
+
x
2
−x+1
Bx+C
A(x
2
−x+1)+(Bx+C)(x+1)=x
2
+1
(A+B)x
2
+(−A+B+C)x+(A+C)=x
2
+1
∴A+B=1,A=B+C,A+C=1
∴A=
3
2
,B=
3
1
=C
∴y=
3
1
[
x+1
2
+
x
2
−x+1
x+1
]
Answered by
0
Answer:
y=
x
3
+1
x
2
+1
=
(x+1)(x
2
−x+1)
x
2
+1
∴y=
x+1
A
+
x
2
−x+1
Bx+C
A(x
2
−x+1)+(Bx+C)(x+1)=x
2
+1
(A+B)x
2
+(−A+B+C)x+(A+C)=x
2
+1
∴A+B=1,A=B+C,A+C=1
∴A=
3
2
,B=
3
1
=C
∴y=
3
1
[
x+1
2
+
x
2
−x+1
x+1
]
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