Question

The fractional change in internal energy when a gas is cooled from 927°C to 27°C is :​

Answer 1

Answer:

T1 = 927 + 273 = 1200 K T2 = 27 + 273 = 300 K Internal energy ∝ Temperature U ∝ T (U1 / U2) = (T1 / T2) ∴ [(U1 – U2) / U2] = [(T1 – T2) / T2] ∴ % change in energy = [{(1200 – 300) / (300)} × (100)] = 3 × 100 = 300%

Explanation:

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