Question

The fractionB3x1 is subtracted from the fraction A2x3. The resulting fraction is11(2x3)(3x1). Then find A + B.​

Answer 1

Given :   Fraction B/(3x - 1 ) is subtracted from the fraction A/(2x + 3)

. The resulting fraction is -11/(2x + 3)(3x - 1).

To Find : A + B =

Solution:

A/(2x + 3) - B/(3x - 1 )

= A(3x - 1) - B(2x + 3)

= (3Ax - A - 2BX - 3B)/(2x + 3)(3x - 1)

(3Ax - A - 2BX - 3B)/(2x + 3)(3x - 1) = 11/(2x + 3)(3x - 1).

3Ax - A - 2BX - 3B  = - 11

=> x(3A - 2B)  - (A + 3B)  =  - 11

Comparing

3A - 2B =  0   Eq1

A + 3B =  11     Eq2

3* Eq1 + 2*Eq3

=> 9A + 2A   =  22

=> 11A = 22

=> A = 2

2 + 3B = 11

=> 3B = 9

=> B = 3

A + B = 2 + 3  = 5

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